ListView listView = (ListView) mRootLayout.findViewById(R.id.listView) įinal MyListAdapter adapter = new MyListAdapter(activity,R.layout.list_row,(ArrayList)myListManager. MyListManager myListManager = new MyListManager(mRootLayout,context) mRootLayout = (LinearLayout) om(context). I didnt need to use fragments or activities.

Then create a regular java class that can be used as the event listeners for the actions within that layout. Ok the correct approach to this appears to be to inflate the layout with in the service class and add it to the windowmanager that way.

is this even possible? How would I do this? WindowManager.addView( imageview, params) īut what I want is to have my own activity on this new window on top of the client apps window. ImageView imageview = new ImageView(this) WindowManager.LayoutParams params = new WindowManager.LayoutParams( I then try to add an image view by doing this windowManager = (WindowManager) getSystemService(WINDOW_SERVICE) After some reading up it seems that adding a new window is what I want to do so I added in this permission. AndroidViewRootImplTerrencehe- ViewRootImpl view ViewRoot Android 2.2ViewRootImplViewRootViewRootImpl.javaWindowManagerDecorViewView. I've also tried programmatically bringing it up with an onFocusListener: tOnFocusChangeListener(new View.I am writing an android library that needs to display an activity on top of the client app. However focusing on this does not bring up the keyboard. WindowManager.addView(mEditText, params) WindowManager = (WindowManager) getSystemService(WINDOW_SERVICE) WindowManager mWindowManager Context.getSystemService(WindowManager.class) you can add a view to Activity in this way. Android System WebView is a component for the operating system which allows apps to display web content. This help content & information General Help Center experience. I have added the 'SYSTEMALERTWINDOW' permission and I have enabled 'Draw over other apps' in app info. Answer (1 of 9): If you really need to re enable it, you should go to the chrome app in app settings disable it, then go to the Google play app store and update/re-install/enable webview.They. I'm writing an application that uses the following code to draw an edittext on the screen over running applications: WindowManager.LayoutParams params = new WindowManager.LayoutParams( package import import import import . WindowManager.addView () causes BadTokenException Ask Question 2 I'm trying to create an overlay window but when I try to add the view to the WindowManager, it gives me an exception.

Android java windowmanager addview